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\[ b^2 - 4ac = 16 + 48 \]
\[ b^2 - 4ac = 64 \]
\[ x = rac{-(-4) \pm \sqrt{64}}{2(2)} \]
\[ x = rac{4 \pm 8}{4} \]
Calculate the two solutions:
\( x = rac{4 + 8}{4} = rac{12}{4} = 3 \)
\( x = rac{4 - 8}{4} = rac{-4}{4} = -1 \)
The solutions are \( x = 3 \) and \( x = -1 \).
#### \( x = 3, x = -1 \)
Find the limit as \( x \) approaches 2 of the function \( f(x) = rac{x^2 - 4}{x - 2} \).