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\[ b^2 - 4ac = 16 + 48 \]\[ b^2 - 4ac = 64 \]\[ x = rac{-(-4) \pm \sqrt{64}}{2(2)} \]\[ x = rac{4 \pm 8}{4} \]Calculate the two solutions:\( x = rac{4 + 8}{4} = rac{12}{4} = 3 \)\( x = rac{4 - 8}{4} = rac{-4}{4} = -1 \)The solutions are \( x = 3 \) and \( x = -1 \).#### \( x = 3, x = -1 \)Find the limit as \( x \) approaches 2 of the function \( f(x) = rac{x^2 - 4}{x - 2} \).