\[ 90 + 4y \leq 240 \]

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• Pour résoudre cela, soit \( x \) le nombre de gadgets A et \( y \) le nombre de gadgets B. La contrainte de travail est \( 3x + 4y \leq 240 \). La contrainte de production pour le gadget A est \( x \geq 30 \).
• Substituez \( x = 30 \) dans la contrainte de travail :
• \[ 3(30) + 4y \leq 240 \]
• \[ 4y \leq 150 \]
• \[ y \leq \frac{150}{4} = 37.5 \]
• Puisque \( y \) doit être un entier, le nombre maximum de gadgets B est 37.

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